What is the enthalpy of vaporization of hexane?
28.9 kJ/mol
The molar enthalpy of vaporization of hexane (C6H14) is 28.9 kJ/mol, and its normal boiling point is 69∘C.
What is the Vapour pressure of hexane at its normal boiling point?
Problem #4: The molar enthalpy of vaporization of hexane (C6H14) is 28.9 kJ/mol, and its normal boiling point is 68.73 °C. What is the vapor pressure of hexane at 25.00 °C?…Solution:
| P1 = 6.91 mmHg | T1 = 0 °C = 273.15 K |
|---|---|
| P2 = 760.0 mmHg | T2 = 68.73 °C = 378.15 K |
How do you calculate enthalpy of vaporization from boiling point?
Tc = 647.3 K and Pc = 221.2 bar (218.3 atm), the heat of vaporization is obtained as 42,060 J/mol….[edit] Using Riedel’s equation.
| where: | |
|---|---|
| Hv | = Heat of vaporization, in J/mol |
| R | = 8.3144 = Universal gas constant, in J/(K mol) |
| Tn | = The liquid’s normal boiling point, in K |
| Tc | = The liquid’s critical temperature, in K |
Why does hexane have a high boiling point?
Hexane has a larger surface area, and therefore the greater dispersion forces and higher boiling point.
What is the melting point of hexane?
156.2°F (69°C)Hexane / Boiling point
What is structural formula of hexane?
C₆H₁₄Hexane / Formula
How do you find vapor pressure from normal boiling point?
To find the normal boiling point of a liquid, a horizontal line is drawn from the left at a pressure equal to standard pressure. At whatever temperature that line intersects the vapor pressure curve of a liquid is the boiling point of that liquid.
What is Delta HVAP?
The enthalpy of vaporization (symbol ∆Hvap), also known as the (latent) heat of vaporization or heat of evaporation, is the amount of energy (enthalpy) that must be added to a liquid substance to transform a quantity of that substance into a gas.
How do you find Delta H of vaporization?
Use the formula q = m·ΔHv in which q = heat energy, m = mass, and ΔHv = heat of vaporization.